That would be taking the square root of both sides, but in order to do that you will have 2 roots: the positive and the negative. So you'll have to account for each case:
x+1 = x or x+1 = -x
The first case ends up being discarded and the 2nd case is 2x+1 = 0. As Sal explained, it's easy to forget this and get the question wrong, you're better off expanding the squared term and solving that way.
Problem number 28....
In the first one, what if x =1, then it would prove it to be 1/2 or .5, which is not an integer????
ajone86 1 year ago
prob 28, was wondering if x was odd ?
vanidharatreya 1 year ago
dese r answers for which questions?
shakthiyj 1 year ago
That would be taking the square root of both sides, but in order to do that you will have 2 roots: the positive and the negative. So you'll have to account for each case:
x+1 = x or x+1 = -x
The first case ends up being discarded and the 2nd case is 2x+1 = 0. As Sal explained, it's easy to forget this and get the question wrong, you're better off expanding the squared term and solving that way.
shell3202 1 year ago
Sal: Thanks for these great videos.
For problem 29
(x+1)2=X2
Cant we not remove the "2"square from both side?
X+1=X
1=X-X
1=0
That doesnt give us value of X. How would we know in exam what to choose?
Thanks
sallo808 2 years ago
very useful info thx
ikipi1 2 years ago
u r great mr salman your videos are really helpful for me and just to comment u i made my youtube account
sadscene1 2 years ago
great!
kadsawy 2 years ago