Perpendicular Radius Bisects Chord

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Uploaded by on Oct 7, 2011

Simple proof using RSH postulate to show that a radius perpendicular to a chord bisects it

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LICENSE: Creative Commons (Attribution-Noncommercial-No Derivative Works).

For more information about this license, please read: http://creativecommons.org/licenses/by-nc-nd/3.0/.

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  • ok so triangle amo is congruent to triangle cmo by rsh postulate and by CPCTC am is congruent to mc so by what thereom or postulate do you know od bisects ac?

  • I don't think it is. The definition of perpendicular is that they intersect at right angles. The segments don't intersect if they don't cross each other.

  • @CadenFeldman So, if I'm talking about 2 non-touching line segments, let's say, the top of a window, and the side of a different window. Is it mathematically legitimate to say they are perpendicular? Or is it only legitimate to say that those line segments "produced" are perpendicular?

  • @armpitpuncher You cannot really assume certain relationships (like perpendicularity) between lines AB and CD say, that don't touch, instead one would write and then go about proving that AB "produced" (the mathematical word for extended) is perpendicular, or whatever you are proving, to CD.

  • My comment assumes that line segments can be called perpendicular even if they aren't touching. Is that assumption wrong?

  • Can a line segment which doesn't cross another be said to bisect it? If not, what about the case where AC is on the bottom half of the circle? Or are we talking about the line formed when the radius OD is extended infinitely?

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