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Centripetal Acceleration (part 3)

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Uploaded by on Apr 8, 2008

How fast does a car need to go to complete a loop-d-loop.

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LICENSE: Creative Commons (Attribution-Noncommercial-No Derivative Works).

For more information about this license, please read: http://creativecommons.org/licenses/by-nc-nd/3.0/.

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  • i never get tired listening to you

    thank you

  • great videos! Sure, but why from one moment to another he start using feet's as the magnitude ? in my country we use meters and I am not costume to feet's. Even do, that's not a big deal.

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All Comments (93)

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  • *it was useful

  • 'i don't know is that was disturbing or useful or confusing' heehee

  • I am very happy to see the vidoe How fast does a car need to go to complete a loop-d-loop after you give this

  • I Love The Video It Can Increase My Knowledge How fast does a car need to go to complete a loop-d-loop.

  • Steady I Really Like This Video How fast does a car need to go to complete a loop-d-loop

  • Watching your videos makes me want to be home-schooled.

  • Sal, your videos are comforting.

  • @bubbleteddies Because Fn and Fg act as Fc (the force towards the center) so I considered both of them when doing the formula Fnet=mac

  • 7.71m/s (for the answer below)

  • Please correct me if I'm wrong but I dont think this is correct. Since you're trying to find the minimum speed it must go to offset the loop, shouldn't you consider Fn as a force as well. Fg and Fn are both going downwards so according to newtons second law the equation would be Fg+Fn=ma. Fn must be 0 as that is the minimum to complete the loop, making the equation Fg=ma. Fg=mg and a=v^2/r so the new equation would be mg=m(v^2/r). Masses cancel out so the new equation is g=(v^2/r) making v=7.71

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