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Solution for Proc-4(2009)-QNo37-Alternate Method

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Uploaded by on Aug 31, 2009

Solution for Proc-4(2009)-QNo37-Alternate Method

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  • ATGC, two possibilities are there for marks distribution among practical and theory exam:

    1. T1,T2,T3=40,60,80 and P1,P2=100,20----Avg. for both is 60

    2. T1,T2,T3=20,60,100 and P1,P2=40,80----Avg. for both is 60

    For Case 1, overall avg. is 400/7=57.14

    For Case 2, overall avg. is 440/7=62.85

    I request the CL to explain this anamoly......there are two correct options...

  • i jus saw dis ... well I may be wrong but ... 300+80+20=400 nd 400/7 = 57.14 which is closest to option b not c... point me if i am wrong

  • Well Ank, not really buddy, u got it wrong there. For 420 u need to have 300 + 120, but to get a sum of 120 with the weighted marks is not possible. Try it out.....make sure u divide the marks among the papers correctly.

  • Isn't 60 X 7 = 420, an integer. Can you please explain ,why 1 was not considered.

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