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Projectile Motion with Unit Vectors

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Uploaded by on Mar 26, 2008

Determining the position vector as a function of time

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LICENSE: Creative Commons (Attribution-Noncommercial-No Derivative Works).

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Uploader Comments (khanacademy)

  • Yeah, it's a given. It would be 9.8 m/s^2 in the metric system. Both only apply to Earth. You can experimentally try to confirm if you have the time.

Top Comments

  • Haven't the americans learned to use meters yet!? Haha! ;P

  • Sal FOR president!!

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All Comments (19)

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  • I am very happy to see the vidoe Determining the position vector as a function of time after you give this

  • I Love The Video Determining the position vector as a function of time It Can Increase My Knowledge

  • Steady I Really Like This Video Determining the position vector as a function of time

  • do you have a video to help me with solving how deep something is based off of only knowing the initial velocity, speed of sound and time it took for you to hear the sound?

  • 5 dimensions?!? AAAAAH

  • Actually the formula given at the top isn't difficult to prove. Let the initial velocity be v and initial position be p. Δd is the change is distance

    In the projectile motion videos, we proved that Δd = vt + at^2/2. Now add p to both sides. Δd + p = p + vt + at^2/x. We know that (initial position) + (change in distance from p, which is change in position) is our finial position. Therefore p(t) = p + vt + at^2/2

  • I made a program to calculate projectile motion thanks to your videos =D.

  • @reztenster

    calculus 2 or 3

  • @Thymonico

    its too easy, we rather do something complicated like fractions

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