Projectile motion (part 8)

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Uploaded by on Nov 2, 2007

A little leftover from part 7

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LICENSE: Creative Commons (Attribution-Noncommercial-No Derivative Works).

For more information about this license, please read: http://creativecommons.org/licenses/by-nc-nd/3.0/.

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  • @DaleSparrow

    Because the ball is in "free fall". From what i can recall, the ball is only being effected by the force of gravity in free fall, so it only has a vertical acceleration (g). It's horizontal acceleration is zero so it's horizontal velocity is also zero.

  • Love Kahn's videos I learn a lot from them, and I may learn to shut my mouth here in a minute, (I'm in a rush and this is in haste) but the final result seems wrong to me:

    Seems like the position function for this topic is:

    -10 m/s^2 (t s)^2 + 25 m/s (t s) + 0

    {x,y}:{ {5/2,0}, {5/4,125/8} }

    h=125/8 vs 250/8

  • which means that it is technically stationary

  • yes the horizontal velocity is constant. It is constant at 0 in this example because the ball is only thrown straight up in the y direction.

  • hes only using Y velocity, don know why

  • hold on... doesn't the ball have a constant horizontal velocity, meaning that it isn't technically stationary at h??

  • Thanks for this video.

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