Uploaded by roulettebot on Sep 10, 2010
http://www.roulette-magician.pro.tc
MIDAS: THE BEST progression type until now and my favorite. Example for RED/BLACK : it will ask you how much you want to win, if you choose 100$, it will ask you to split that money into peaces like 25$,25$,25$,25$ and store them into an array. It will start to bet 25$ and if it wins it takes the next bet (25$) and the last one (25$) and it will bet 50$, if it looses, the 50$ are memorised at the end of the array, and the next bet will be the first one in the array. If the bet is 25$ and your available bankroll is 20$, it will substract a part of your bankroll and bet less than the 25$ bet. When the last bet is won the progression is terminated and you have won 100$. Later I will add another way to choose the bets: choosing the lowest bet in the array without making the sum of the first and the last bet values.
PARLAY: This is one of my favourite progression types. when you win the money is put back on the table until your winning goal is achieved. Example for RED/BLACK : wait 1-4 times for the same colour to appear and take the money when you win 128$, very good when the same color comes in a row.
GUETTING: it uses 4 levels with 3 bets each like {1}, {2, 3, 4}, {5, 7, 9}, {11, 16, 21}
It will start to bet 1$:if it wins it bets 1$ again (when winning it will allways bet again the same ammount of money), after winning the second time the bet will become 2$, if this bet is lost it will drop to 1$ and stay there until it wins. If the bet was 5$ and lost, it will go back to 4$ and then to 3$, to 2$ and then to 1$ in the case of repetittive losses. You may choose from 2 options: "Same color" will bet on the last color, or play "n other" choosing from 2 to 5 . When "n other" is selected and the limit is set to "5" , the robot will bet on the other color, after RED appeared 5 times in a row, the robot will continue to bet only on RED until the color changes.
STANK: known as range. Example for RED/BLACK : if you choose range 11 the bets are stored like this: 1$, 2$, 3$, 4$, 5$, 6$, 7$, 8$, 9$, 10$, 11$. The first bet will be 6$, if it wins the next bet will be 5$ but if it looses the first bet, the next one will be 7$. If the 1$ is won it will remain at 1$. When the 11$ bet is lost the progression is terminated and another one will start from 6$. As long as your bet is under range+1/2 you are in profit, if you reach the maximum range (11 in our case - you lose money).
ELROD: it has 3 elements: 100$ debit, 20 the control number and the bet=100/20. The first bet will be 5$, if it wins, the debit becomes 100$-10$=90$ the control will be 20-(10$ won/5$ bet) that means 18, and the bet becomes 90$/18. If the first bet is lost, the debit will be 100$+5$=105$ the control remains at 20 and the bet will be 105$/20. When winning, if debit is less than control the progression is terminated, you have won and everything starts from debit=100$, control=20 and bet=5$.
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Nmproful 1 year ago
Hi, are tehre any specific setting to win?
Ty.;>
Nmproful 1 year ago