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Physics 3.5.4a - Projectile Practice Problem 1

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Uploaded by on Oct 26, 2009

Practice Problem on Projectile Motion.

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Uploader Comments (derekowens)

  • @derekowens why when we take the horizontal the acceleration is zero? please tell me

  • @Star123Euro In this problem, the object is a projectile, which means its motion influenced by gravity only. And gravity pulls straight down. The force of gravity does not have any horizontal component, so the horizontal acceleration is zero as long as it is in free flight.

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All Comments (72)

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  • Your videos on physics help me out so much!!! thank you so much for uploading these!!! :)

  • @804YankeeFan The buoyant force is very tiny, and is generally considered small enough to ignore. One could, though, include both the buoyant force and the air resistance in the calculations. The calculations get beyond the scope of this course, though.

  • @derekowens I was wandering If I drop a ball in the air, the air's bouyancy force is acting on me and accelerating me with the weight. Am I right? So why dont people consider the extra bouyancy force?

  • Thank you so much for these uploads.

  • I <3 you man, no homo.

  • @derekowens So, I have a last question I was wandering about. So are satellites orbiting the sun with the Earth while they are orbiting the Earth? Does this cause the Earth to be an inertial reference frame when calculating its orbit?

  • @HairtUB It depends on how the problem is set up. If it is set up consistently, then y and a will both have the same sign in that equation, and there would be no negative square root.

  • @804YankeeFan Yes, that's basically correct. When I throw a ball into the air, the rotation of the earth does not cause the ball to be "left behind".

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