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Newton Raphson Method: Derivation

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Uploaded by on Feb 18, 2009

Learn how to derive the Newton Raphson method of solving a nonlinear equation of the form f(x)=0

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  • How do I find use the tangent to find the initial estimate?

    I have a graph of two curves; (y=e^x) and (y=4/x)

    And it says I have to find the initial estimate for the root of the equation: x e^x - 4 = 0

    The answer is that the solution is the intersection of f(x) - e^x and f(x) = 4/x but that doesn't help me find the actual NUMBER for the initial estimate.

    How would I go about finding the initial estimate NUMBER?

  • @xTabbyCat I do not know of a general technique to do so. If the problem is connected to a physical phenomenon, you can use the knowledge of the physical problem to choose a good initial guess. Go to numericalmethods(.)eng(.)usf(.­­)edu and click on Newton Raphson Method. Click on the textbook chapter to see a physical problem.

  • Sir, could you help me with this question?

    Use the Newton-Raphson process to determine a value of x near x1 = 0 for which f(x) = 0, where

    f(x) = 9 x+0.4−8 sin( x )

    giving your answer (and the interim results we ask for) correct to 5 decimal places. What are the values of x and f(x) at the second iteration?

    What are the values of x and f(x) at the third iteration?

    The value of x (correct to 5 decimal places) such that f(x) = 0.

  • @fullheavy Just follow the example given in the Newton-Raphson playlist. It is not a difficult problem to do. Be sure that your calculator is set to the radians mode. Once the 5 decimal places do not change in the answer, you have your answer.

  • What mean by Es?

  • @MachiP0p0 Es means pre-specified tolerance. It is a stopping criteria to stop iterations. When the absolute relative approximate error is less than pre-specified tolerance, then we can stop the iterations. How do we choose Es? Go to numericalmethods(.)eng(.)usf(.­)edu and click on Measuring Errors under Introduction. See pages 5-7 of the pdf file of the texbook chapter.

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All Comments (17)

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  • hi.

  • NUS HIGH!

  • Nice very clear

  • Thanks agian....another ace on exam in a few hours...u are a great teacher

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