Area of a Kite
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Uploader Comments (dangarbo10)
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All Comments (5)
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Thanks man :)
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Dudeeee ily you make it soooo easy. :D
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btw, love your t-shirt xD!
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Thanks i needed for my homework couldn't remember how to do this. :)
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Great explanation, but isn't it possible as well like this. Let's call the intersectionpoint of the diagonals S. You then put triangle ABS upon BCS to form a rectangle and you can put triangle ASD upon CDS to form another rectangle, laying next to the first. The area of the two rectangles combined is 0.5*AC*BD, so 0.5*d2*d1. That's how we did it, I found it to be a little easier :-) Your way is interesting as well, though, and I think it's better, mathematically!
- Someone from Holland
Jeroentjepianotje 3 years ago
yeah - that sounds like a great way to do it
dangarbo10 3 years ago