Lagrange multiplier example: Minimizing a function subject to a constraint

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Uploaded by on Apr 17, 2009

I discuss and solve a simple problem through the method of Lagrange multipliers. A function is required to be minimized subject to a constraint equation. Such an example is seen in 2nd-year university mathematics.

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Uploader Comments (DrChrisTisdell)

  • I thought you always ADDED the Lambda(constraint) to the objective function? you have it as being subtracted. Does it not matter because you are essentially adding or subtracting zero?

  • @H60hadgi It doesn't matter. The reason goes back to the proof of the Lagrange method (that is, why it works). The idea is that at points of max/min there is a number lambda such that grad f = lambda (grad g), that is, the two vector grad f and grad g are parallel, so you could write it as grad f = - lambda (grad g) instead and this still accurately says that the two vectors are parallel.

  • Thank you very much for this lecture! What if there are additional inequality constraint x>=0,y>=0,z>=0, how can we use lagrange method??

  • @YumiKondo0911 If you add those extra constraints to this example then there is no solution.  Can you see why?

  • thats an easy example, can u show some more dificult ones? related to the part where we need to be "creative".

  • @KillerChaijBalin /watch?v=mFTNEkFveaY and start at 20:39

Top Comments

  • I LOVE LAGRANGE!!!

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  • thanks . 

  • Mr Tisdale, Thank you for making this video.

  • awesome video, thanks!

  • THANKS...IT HELP ME VERY MUCH TO UNDERSTAND

  • THANK YOU VERY MUCH  RESPECTED SIR.

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