Trigonometric Integrals - Part 6 of 6

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Uploaded by on Aug 17, 2008

Trigonometric Integrals - Part 6 of 6. In this video, 3 trigonometric integrals that do not fit any one technique are discussed. For more free math videos, visit http://PatrickJMT.com

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Uploader Comments (patrickJMT)

  • I don't go to classes, watch your videos and get good grades on my tests :) thank u!!

  • @VKM7md :) go to class.

  • Patrick

    you make calculus 2 look like 1+1=2!

    thanks

  • @ricky23i you are very welcome :)

  • For the integration of Csc(x)

    why can't I just differentiate it as 1/sinx

    than let u=sinx

    and integral (1/u) = ln(u)

    ln(sinx)?

  • @lintingche2012 what about the du? you should rewatch u-substitutions. according to what you are saying, integral of 1/(anything) = ln(anything). take the derivative of ln(sinx) and see if you get csc(x); if not, something is wrong (and it is!)

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  • Hey Patrick! I believe you made a mistake in the first problem.. you have two minuses in your answer so you should get a positive 1/2cos2x! Anway thanks for posting these videos up they were extremely helpful! :)

  • @lintingche2012 if you let sinx = u, then it follows cosxdx = du, but u dnt have cosx in the numerator.. if the given is cotxdx the answer will be ln(sinx)

  • am lost in this part 6 patrick

    

  • Watch Patrick videos

    Drink lots of coffee

    Study study study

    Profit!

  • So this last part of trig integrals is basically for any problems that you wouldn't be able to approach using the other five steps without doing some trig identity or algebra first?

  • thanks patrick!!!

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