Newton-Raphson Method: Example
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Fantastic, saw this after my lecture and now its all a cake walk! off to book exercises!
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Great job. I just needed a refresher on how to work through this iterative method to find a numerical solution to a circuit problem that I'm working on and this helped oodles.
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This is great. Thank you PAAJI!
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@numericalmethodsguy TRUE
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You explained it very well. Thank you very much!
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This is one "racial" video. =p
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@numericalmethodsguy so basically the initial guess closer to zero the better? like in your own function: if x=3 then x^3-20= 7 if x=2 then x^3-20 = -12 ...7 is closer to 0 than -12 so the best initial guess would be 3 along with 2.9 2.88 2.87 etc..? By the way thanks for good references it would help me alot.
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@vitalcoordinates All your prof is trying to do is to start with a good initial guess, and "almost" ensure that you end up finding the root you are looking for. Go to numericalmethods(dot)eng(dot)u
sf(dot)edu and click on Keyword. Click on Newton Raphson method. Read the N-R method textbook chapter.
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Why is it that for the 3rd iteration when I do it I get 0.37% for my relative approx. error? I do it just as Ea= [(2.714-2.715)/2.714] * 100 and I get .37%. I double checked with multiple calculators yet I am puzzled as how you got .009%. Can you please explain or anyone do the math at 8:12 in the video and tell me how you got it. Thaks
dmwirichia 1 month ago
@dmwirichia You are partially right. You should get 0.037%. The number 0.009% was obtained using more significant digits in the calculations of the roots.
numericalmethodsguy 1 month ago
thanks for the video.
is the value of x1 correct?
avp9037 2 months ago
@avp9037 It is correct:
3-(3^3-20)/(3*3^2)=2.741
Do you get a different number? If so, let me know!
numericalmethodsguy 2 months ago