Energy Propagation
Uploader Comments (tortuga0303)
All Comments (55)
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@xsports49 Series & parallel LC circuits act in a reciprocal manner. Series LC at resonance acts like zero resistance, & the parallel LC at resonance acts like a very large resistance. Reactance X & impedance Z of a series circuit versus susceptance B & admittance Y of a parallel circuit. Capacitive reactance is a negative complex number & when added to the positive complex number of inductive reactance can give a very near zero value. Admittance is a reciprocal of a possibly zero difference.
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@TheBblindman On a closely or strongly coupled core, the loading of the secondaries does affect the primary through mutual induction, & in the radio station example people far away don't get a strong signal. Because the secondaries are resonant passing rather than blocking current, the coupled loading would increase. Lenz's law plays a role. Counter-EMF is affected. Primary inductance appears reduced. More primary current flows so more source power is drawn costing you money--not free at all.
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@TheBblindman On a closely / strongly coupled core, the loading of the secondaries does affect the primary through mutual induction, & in the radio station example people far away don't get a strong signal. Because the secondaries are resonant passing rather than blocking current, the coupled loading would increase. Lenz's law plays a role. Counter-EMF is affected. Primary inductance appears reduced. More primary current flows so more source power is drawn costing you money--not free at all.
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when you tune the frequency to extinguish the light bulb on the primary what are you doing to the frequency. turning it faster or slower. please help I'm new to this.
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awsome lecture
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Thank u .
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very nice! cop almost 1, put 2 or more secondaries on same core, tune them all together, than u will have same cop<1 x number of secondaries. Guys do the math! Its functioning exactly like a radio station with the emitter being the primary! One doesn't have to put more power in the emitter of a radio station if the radio station has more receivers (listeners)! A radio station is a simple proof of unlimited cop. Resonance is all!
Also try to saturate the core with some Nd magnets.
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Very informative video and well done. Thank you for sharing it.
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But nice. We to can shine in house with bulbs from torch will now
A series LC acts as a short circuit at resonance, while a parallel LC acts like a huge impedance.
tortuga0303 1 year ago
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I had watched this video some time before, but when I watch it again now it just hit me so much harder. The experiments speaks for themselves, and you are saying something without really saying the naughty word. Thank you!
Nabo00o 1 year ago
@Nabo00o
This is not free energy yet, but a reactive impedance matching transformer. I think most of the great minds in this area have gone down the "resonance road" and while long, it is fruitful at the end.
tortuga0303 1 year ago
@tortuga0303
Thank you for your answer. Maybe I was too quick to conclude here.
But one aspect of this and your later tesla coil demonstration bothers me; if you are supplying current to power the lamp here or the motor in tesla coil demonstration, then this current should also pass through the primary bulb.
And it seems to me, that no matter what the current and voltage phase is inside the tank, the input is 12 volts, and if you spent energy on it the current should light the bulb.
Nabo00o 1 year ago
@Nabo00o
The bulbs take some 3v 300ma to light up. The input is 12v. Therefore it is possible that the input be say 12 v @ 75ma. Then through the impedance matching quality of the transformer, the output is reduced to 3v 300ma. power going in and out is the same, but one is of the correct quality to light the bulb and the other is not.
tortuga0303 1 year ago
I would like to ask, where does the energy come from in the secondary to light the secondary's bulb? It is supposed the high impedance of the primary LC circuit prevent the current to circulate, no? Can I use CMOS555 PWM circuit to replace the SG there?
aaron5120 1 year ago
The bulbs need several hundred miliamps to light. Below this threshold they are dim if not lit at all. The first bulb has going through it 12v, but few miliamps making it dim. The second bulb is impedance matched bringing the 12v down, and the amperage up, therefore lighting the second bulb. All the power is going through the first bulb, but in a form which is not suitable for its incandescence.
tortuga0303 1 year ago