bitt power factor 2 .wmv

This video is made for my better understanding of the possible use of the BITT from Thane Heins .
The shematics are of course ideal case, and assuming that the BITT works properly as per the video from Thane Heins when he make comparison from the BITT versus normal transformer (see his video channel)

Discussion at OU in the thread of Dr Steven Jones

OK hope this helps

Laurent

• Category

  Science & Technology

[KONGNO2000]

how about pulse dc, will it also work on this kind of transformer??

[kdkinen]

you rock Woopy, have you seen my recent replication?

[User2718218]

3rd: The bottom line is this: If you have a perfect 90 degree phase shift showing a power factor of zero then the moment you start to drive a real load the phase shift is not 90 degrees any more. However, if you are not extremely careful with your measurements you can trick yourself in to believing that the phase shift remains at 90 degrees. If your waveforms are not pure sinusoids, then you can't even rely on the observed phase shift. In many of Thane's clips the waveforms are distorted.

[User2718218]

2nd: In lots of Thane's clips he overdrives and saturates the input and you can hear the 60 Hz power line hum and some power is being burned off in the transformer itself. When Thane puts a small load on a secondary coil then the phase shift might only change from 90 degrees to 89.5 degrees and you can't see it on the scope. Another problem is the voltage and current traces are not pure sinusoidal waveforms. That complicates the power factor measurement and you need a DSO and math.

[User2718218]

Woopy, my estimate when I look at your schematic for the BITT arrangement is that you will see real power being pumped into the center coil from the windmill generator. When the phase shift is exactly 90 degrees then there is no real power and only reactive power. So if the phase shift is 89 degrees there is a small amount of real power and mostly reactive power. It can be very hard to see a difference between an 89 and 90 degree phase shift by looking at a scope display.

[User2718218]

There is no need for a ground in this setup. The differential outputs from the two secondary windings are independent from any ground and don't need a ground. Attaching either side of either of the secondaries to a ground will make no difference in the efficiency. The only thing that will do will be to tie one or both of the secondairies to the reference potential of the ground but no current will flow through the ground wires.

[UrCoffeeTastesToasty]

you can eliminate most windmills with such a good transformer!

[onthecuttingedge2005]

make the load go to ground, even more efficient, still, I would rather look at tree's rather than a forest of windmills.