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Esto no es radiante ni ondas escalares

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Uploaded by on Apr 29, 2010

Este efecto se produce por la descarga continuada de la bobina que transforma la tension. Aqui teneis el esquema http://img571.imageshack.us/img571/695/98446287.png

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Uploader Comments (aaaalexisss)

  • Mira esto es tan sencillo como que la corriente que enciende la bombilla proviene del colapso de la bobina que proviene a su vez de la corriente utilizada para magnetizarla, si esta corriente del colapso se mide se consigue un 99% de la corriente que se utilizo para magnetizar la bobina, nunca el 100% y por supuesto que no tiene nada de energia radiante, es puramente induccion magnetica, solo hay que estudiar el funcionamiento de la induccion para entender este experimento.

    NO HAY RADIANTE.

  • No es tonta en absoluto. Se calienta muchisimo hasta el punto que el filamento se va deteriorando y se funde pasados unos minutos. No creo que sea energía radiante ni ondas escalares ni nada de eso.

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  • @aaaalexisss

    Buen comentario. ¿Podrias darme datos sobre la bobina? La seccion del hilo, el numero de vueltas y el nucleo que usaste. Gracias.

  • @MrMagAmp

    excellent let me update and send to me the complete schematic

  • @aaaalexisss

    ¿Puedes darme datos sobre la bobina?

    El diametro del hilo usado, el numero de vueltas, y el nucleo.

    Gracias.

  • @TheIronStark

    Yes, the circuit works fine, but only is present the half of the technique needed to produce magneto-dielectric energy. The power source (secondary), must be a HV-DC Capacitor, and it's must be pulsed for a brief period of time.

    Using the Back-EMF directly, is to use an incomplete technique. I have contacted with the author to improve the circuit.

  • @MrMagAmp

    Part2:Your friend should check the quality of his transistors for to get a sharp switching state and a coil wire sufficiently thick for to give an strong (high amperage) back emf and sufficiently long wire for to give an high voltage back-emf and regulate the frequency and duty cycle etc..... a good idea? use a larger ferrite toroid and a thick copper insulated wire.... you will see maybe @ 28 Khz... or about :-)

  • @MrMagAmp

    Hi, electricity and magnetism are directly connected so in the wire lamp is the reversing current that switch the magnetic domain of the nucleus of the atoms in the wire of the lamp for this reason the lamp is sending that kind of blue light and that light is "radiant " event just because is that wire that is "radiating" the zero point energy.... in fact is light X 10 with different colours, The same kind of light of the "Vacuum triode amplifier" from Mr. Sparky Sweet now death.

  • @TheIronStark

    Yes, if there is current and heat, there is not radiant energy, but you need to know that the technique shown in this video is not as complete as the original technique used to produce electrostatic/radiant energy.

    The light bulb must be powered directly from a capacitor, and there should not be a direct connection between the light bulb and the power source.

  • @aaaalexisss

    Gracias por la respuesta. Si bien tu demostracion es fenomenal, seria conveniente hacer unas pequeñas modificaciones. La bombilla no se esta alimentando desde un condensador, entre otras cosas.

    Cuando leas este mensaje ponte en contacto conmigo y ampliamos el circuito.

  • yes you say right if the bulb is warming it's not radiant energy but you should not put the 1n4007 diode

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