CCNA CIDR subnet review
Uploader Comments (systemerror11)
Top Comments
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stupid troll....
All Comments (46)
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Hey thanks for the refresher. I graduated with an associates in IT, but I have a job in logistics. Nonetheless, I have to move and switch jobs and I will be doing IT work. So I will venture in review for a month to shake off the cobwebs and get back in the game. Again, thanks.
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Neat. Now the Story is clear. Thanks for your time in this. Appreciate it mate.
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you are totally wrong in this video !!!
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the way you talk is very funny, oh look at that :-) Great tutorial
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You nailed it man, neatly.
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i appreciate your effort but for someone who knows ip addressing but want to understand CIDR....this is bit confusing!!!
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definitely subscribing...love this vid. Great job!
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amazing
this is by far the most informative tutorial i have ever seen.
you have earned the subscription my friend
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Good job explaining this... just reviewing but good attitude you have! Congratulations for the time spent sharing this with our fellow admins.
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@guitarmagic23 your telling me. my teacher has the thickest accent ever, and i only understand half of what he says.
WOW! ive been stuck in this lesson for a long time coz my instructor in ccna class sucks!
by just following your instruction, i got 20/20 correct answer from ccna practice activity! thank you very much!
guitarmagic23 1 year ago 4
@guitarmagic23 Awesome. My pleasure.
systemerror11 1 year ago
can i get this power point copy ? please send me a link to download.
sanujee 1 year ago
@sanujee Sorry man I made it quick on the fly using open office a long time ago and have no idea where it is, if it still exists.
systemerror11 1 year ago
Excuse me, I have a problem about how to get the list "0, 64, 128, 192" on 7: 04
would you please further explain it to me? Thx : )
voilethht 1 year ago
@voilethht Sorry man I havent been getting messages on comments apparently.
The way to get the list is to manually write out the bits in the octet, like in 2:24 - then once you have that then back to 7:04 you are borrowing 2 bits from that last octet which brings you to 64 (64 is the 2nd bit in the octet)
Hope that clears it up a bit
systemerror11 1 year ago