Multiple Integrals 13: Evaluation of Polar Double Integrals
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@NMLP1 Well, I didn't watch it, I saw the introduction and moved on.
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@jiramate99 then why u watching video
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2x speed!!!!!!!!!!!!!!
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captions are hilarious
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@NMLP1 Well, seriously. This is pretty easy stuff. Its almost hilarious.
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@jiramate99 dont be a noob.
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def helped me out. thanks man.
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it'll be great if your accent can improve!
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I think there is a theorem of advanced calculus about the Jacobian in coordinants transforms.
Double integral of f(x,ydx.dy)in R=
Double integral of f(g(u,v),h(u,v)*Jacobian[(x,y)
/(u,v)]du.dv in G
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An easier way of considering the geometry of "r.dr.d(theta)" is as follows.
By definition, arc length = r.(theta) .
Hence, d(arc) = r.d(theta) .
The area of the small rectangle equals to the arc length times the small change in r. In the limit, this becomes accurate.
Hence, dA = r.d(theta).dr .
bigstas503 3 years ago 5
thanks a lot donny you're a life saver!
sodown 2 years ago 2