d/dx of integral of f(t)dt from 0 to x
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i'm doing a simple question and i can for the life of me figure it out: g(x)=integral between x and 0 is f(t)dt.evaluate g(0),g(1) so on.when i integral should i not get (t^2)/2? because when i then sub in x and 0 i get (x^2)/2 and 0 so for example i thaught g(1) should equal 0.5 but apparently the answer is 2? could someone help please much appreciated
TheHeartOvALion 1 week ago
Hey can you explain the integral of e^(-x^2)?
i cannot integrate by parts and it seems impossible to me. i can try taylor series but i don't want to make it very messy.
i heard the integral is an error function but i have no idea what that is. the gauss error function?
Forman6 1 year ago
I have to thank you!!!!!
after the AL exam, I put it aside and finally met such questions in the fresh year in university, luckily click in this tutour class by google search!!
2142cristiano 2 years ago
you just saved my homework... thanx ^_^
tanhyaa 2 years ago
it would help to use thicker marker or write bigger.
pberrios0223 2 years ago
What if f(t) = 1/t² ? Does it hold true?
kashiark 2 years ago
That sure made it look so simple. I need lotsa practice tho.
Tonyjava 2 years ago
sqrt(1-t^2) represents the upper part of a circle with radius 1. It becomes solvable with a substitution for t=cos(theta) an then applying trigonometric identities and then recalculating the 0 and x with respect to theta, anyway, that was not the intention of that video, but it's solvable
CPBach 3 years ago
yeah, he missed it.
BernardoDW 3 years ago
excellent
majere95 5 years ago