Motor update. Making use of extracted energy.

most recent schematic and latest developments to the motor.

Category:

Science & Technology

Tags:

• Bedini
• SSG
• Motor
• Energy
• Generator
• Technology

[mixcev]

good job!!

....but.. i think for the best extraction of extra energy, the coils should be energized with nsnsns alternating poles, not nnnnn....

try it with alternating poles, its how generators should work...  i tried measuring the output of the extra coil on my ssg, but it cant produce anything with all north poles out...

all the best

[Drevtoobe]

Hey Blackie! lol

Check out this clip: watch?v=d58RHwFc6oI

It's from the user truthmovementuk. He might be close enough to become a mate of yours.

Just keep your hands in your pockets and watch the blinking lights.

He is missing the current programming resistors for the LEDs and he has a trick up his sleeve... an opto-isolator. Heavy stuff man! lol

[Drevtoobe]

Lower EMF from any stand-alone coil could be boosted by putting a 2:1 or 3:1 transformer between the coil and the FWBR. That would "squeeze out" more power from the coils to pump current into the cap bank by increasing the conduction angle.

Heck, even a coil that only generates 2 VAC when the rotor is at full speed could generate 20 VAC just by using a 10:1 transformer.

Of course adding transformers would give you more voltage to work with, but not any more power!

[Drevtoobe]

But even in your current configuration when the cap bank voltage is lowered, all of the coils start to pump current into the cap bank. The coils that may be "weaker" and generate less EMF will still discharge into the cap bank but with a slightly smaller conduction angle. Ultimately both setups draw from all of the generator coils when the cap bank voltage is lower.

Stand-alone generator coils also generate less EMF than your current setup with the coils in series.

[Drevtoobe]

Yeah that's a tough one with a Bedini motor, you put a load on the rotor and it slows down, and then you are getting less pulses per second from the driving coil to power the rotor.

I am not sure that the three-phase arrangement will produce significantly more power than your current arrangement. Certainly it gives each coil its separate time to pump current into the cap bank.

[Pwordchernoir]

so far im reading ur comments thinking yep, nice, phasing, got it. i can tell you about finding the ideal load though, that as u mentioned above, the rotor croaks as the coils demand too much from it at an already decelerated speed.

[Drevtoobe]

Anyway if you are tempted to try this three-phase setup, I have a challenge for you:

The challenge is to make power output measurements for the current setup and then do the same thing for your next setup and compare the results. It's all so easy to do, just put a resistor across the regulator output, measure the voltage, and the measure the resistor value out of the circuit.

It would be nice to see some real data, and see this related back to the real current consumption of the motor itself.

[Drevtoobe]

You can simplify this if you assume that you want to get the most possible current at 12 volts DC output from the regulator. In this case, you simply lower the value of the load resistor, and the regulator starts to demand more and more power from your generator coils to maintain the output voltage. So you do this until the output from the regulator starts to croak, which really means that the coil power generation is croaking. The rotor may even croak as the coils offer ever more resistance!

[Drevtoobe]

Assume a 1.5 volt Alkaline battery has an output impedance of 3 ohms. If you put a three ohm resistor across the battery, you will measure 0.75 volts across the battery and have 250 milliamps of current, for a power output of 0.1875 watts. For any other resistor value, you can do the calculations and you will find that you always get less that 0.1875 watts. The three ohm resistor is the "matching" load resistor for the battery. That concept applies to your generator setup also.

[Drevtoobe]

I use the term "matching load resistor" because whenever you have a power source driving a load, there is always a certain value of a load resistor that draws the maximum power from the power source.

Here is a simple made-up example: Batteries are modeled by an ideal voltage source in series with an output impedance resistor.  If the load resistance is the same as the output impedance you get maximum power transfer.