Parallel and Series Capacitor Calculations

In this video i am explaining how to do calculate total capacitance and voltage rating of capacitors in parallel and series. In parallel capacitance adds together, and the voltage rating takes the lowest voltage of one capacitor, like if there 2 capacitors in parallel one has a rating of 100 volts and the other has a rating of 10 volts, then the rating of the 2 would be 10, because they both have the same voltage across them in parallel. In series, the capacitance "divides", if you have to capacitors in series each rated 100 microfarad, then the total capacitance will be 50 uf. if they are different you have to use a formula that i show on the video, and if there are more than 2 you have to use a reciprocal, and the voltage adds when capacitors are in series. they work the exact opposite as resistors, same formulas just backwards.

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[lukeBishopp]

hey thanks for the vid really helped with my college assingment and you wouldnt happen to know how to get the charge in a series circuit with the voltage a total resistance in series??

[fnaguitarplayer9]

@lukeBishopp glad to help! sorry i don't understand your question, what do you mean by charge in a series circuit?? thanks for watching

[missjessiebarry]

Thanks dude, you helped me a lot with my electronics homework :)

[fnaguitarplayer9]

@missjessiebarry no problem! glad to help! thanks for watching

[LegendaryDTO]

thank you very much friend :)

[fnaguitarplayer9]

@LegendaryDTO no problem glad to help, thanks for watching!

[fnaguitarplayer9]

@fnaguitarplayer9 equal 6/1 so it would flip to 1/6 or .167 hope this made sense. thanks for watching

[fnaguitarplayer9]

@missjessiebarry no problem. with capacitors i parallel you would just add the values together, and the voltage rating would equal the lowest rated capacitor. in series you use the reciprocal formula, for just 2 capacitors in series it is C1 X C2 / C1 + C2 then that equals the total capacitance and the voltage adds together. For more than 2 in series use reciprocal formual, C1/1 + C2/1 + C3/! = CT/1 then you you flip the final answer, so if you had three that was say 1, 2, 3, then it would...

[missjessiebarry]

Thanks dude, how do you calculate the capacitance when the C1 and C2 are different?