Physics Lesson: Acceleration Equations Part 3 Kinematics for High School
Uploader Comments (PhysicsEH)
Top Comments
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i love your explanations. THANK YOU!! i hope i do good on my quiz tomorrow! :/
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AS I SAID BEFORE YOU ARE A FRICKIN GENIUS MY FRIEND!
All Comments (54)
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I honestly couldn't be more thankful for you guys doing this, I go to a private school and my teacher can not teach, he literally just assigns the homework and expects us to know how to do it... Thank you very much for doing this! Also is there a certain textbook that you like more than others? The one my school is currently using is Nelson Physics 11.
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i love you
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i dont get one thing shouldn'nt vi=o because we r trying to fing the verticle distance of the building
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i cant believe i was having trouble before it all seems so simple now thankyou :)
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When we trow projectiles or anything in the air, does is still have the velocity it had when it was moving with the Earth on the ground?
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@bat974rtiuo in that case it depends on whether your working with or against gravity if it is a free fall problem then it is just 9.8 because you working with gravity, if your throwing something up and determining how high it went then it would be -9.8 because your working against gravity
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@carterandminecraft i know i am asking why is it -9.8ms and not 9.8ms
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@bat974rtiuo that is the acceleration for gravity on any object
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i am taking this as a freshman and its been a pain in the ass i don't have trouble with the map i always pick the wrong equations though so i've been making consistently low grades but i think these videos will help
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Why is the acceleration -9.8ms?
I used these videos to help me review helps a lot!
Kidjaytrack 4 months ago
@Kidjaytrack Thanks for the comment. Glad we could help.
PhysicsEH 4 months ago
my math is a little rusty, i follow how you're plugging the numbers into the equation but just for sake of my memory, do i treat the equation like: (1/2 x a) x (t^2)? as opposed to 1/2(a x t^2) or anything. also, could i use: v2 = v1 + at? because we have v1 (5m/s), a (-9.8m/s^2), and t (3s)?
DamiaanVDW 5 months ago
@DamiaanVDW (1/2 x a) x (t^2)? and 1/2(a x t^2) will give you the same answer so which ever is easier for you to do will work. Yes you can use V2=V1 + at We used this equation at time 3:35
PhysicsEH 5 months ago
question about how you solved part a. Does it make a difference that the ball has been thrown up before it falls? Like if another person did NOT throw it up but simply allowed to drop down the entire time, would the answer to the height of the building change? Because the there's been a certain amount of time elapsed for the ball to go up and then fall down
AikoKayo 5 months ago
@AikoKayo If the ball was not thrown up then the initial velocity (V1) would be zero. The answer would be the same because the equation "knows" that in the first case the ball took time to go up, stop and fall back down. In the second case the equation "knows" the ball just fell down. This is because the "d" is the displacement and the equation calculates the length from where it started to where is ended no matter what path it took (as long as you put in the right info). Hope this helps
PhysicsEH 5 months ago 2