Using the Ratio Test to Determine if a Series Converges #1

Using the Ratio Test to Determine if a Series Converges or Diverges - Two examples are shown. In another video, two more examples are shown! For more free math videos, visit my NEW site http://PatrickJMT.com

Austin Math Tutor, Austin Math Tutoring, Austin Algebra Tutor, Austin Calculus Tutor

Category:

Education

Tags:

• math
• calculus
• ratio
• test
• series
• diverge
• converge
• divergent
• convergent
• absolute
• convergence
• medina
• washington

[limetang]

Do you have any videos of a proof for the ratio test?

[patrickJMT]

@limetang no, i rarely do proofs since i figure they are already in the book! i have thought about doing some though

[mytwohands]

Thank you so much for these videos, Patrick. I got through Calc 1 (online!) with khanacademy, but he's really lacking in Calc 2. I ended up finding your videos instead. I have a feeling they are going to get me through the rest of the Calc series. All your sequence/series stuff has been so helpful.

[patrickJMT]

@mytwohands tons of calc stuff here ; )

[alrasw]

I tag myself (alana) and you (patrick) in your drawing at the start of this video!!

Luv u!

[patrickJMT]

@alrasw hahahaahha!

[patrickJMT]

@ironhead161 clemson must come to me.

[patrickJMT]

@chengyman2009 well, yes, you can teach yourself this stuff (do not see why not), but it is also new to most people and a bit confusing so it can of course be hard to teach yourself.

there is no way to do math other than to practice. also read the proofs and think about why the results are what they are. to me, there is a lot of rules, but they all make sense because i have not just memorized them but also have taken time to understand WHY they are that way.

[FruitsClippers]

I really like your clear and concise notes! Keep it up!

[mrthatguyification]

@vaticanantichrist you have (n+1)^2/(2^(n+1) * 2^n/n^2 , for the first denominator you can separate 2^(n+1) into 2^n * 2^1. so the 2^n that we just created and the 2^n on the second numerator cancel and you're left with the first numerator(n+1)^2/2^1 * 1/ second denominator ( n^2)

[vaticanantichrist]

@patrickJMT Can you help me? In the video @ 2:40 you reduce the 2^2+1 to a 2 i cannot see how you possibly got that? If you reduce from the 2^n everything should go away. I am confused

[Filmrdian]

@killerfox67 Basically when you have two to the n (some integer) and 2 to the n (some integer) plus one more, the 2 to the n parts cancel, leaving just the one more, one.

I'm not sure if that makes sense, but that's how I work it out in my head as I'm doing the problems.

[xxTH3EMPIRExx]

How do you no pass out from all the sharpie fumes? great vids btw

[AasinApples]

@SuperPointz lol for some reason i just found it funny seeing a comment like that on calculus video.

[SuperPointz]

DAM his sigmas look sick

[kenikozo]

I FUCKING LOVE YOU

[ian559fresno]

hahahaha this is the exact same problem in my book :D

[ian559fresno]

Why is this class so hard? Thanks for the videos.