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Uploaded by PengTitus on Apr 24, 2007
柯西不等式的代数证明
Education
Standard YouTube License
這講的太讚了
tmwcfh 2 weeks ago
unbelievable video!
zengrz 1 month ago
amazing 太棒了!
cyberlancer 2 years ago
sry but why can u change the first equ to (a1+tb1)^2 + (a2+tb2)^2.... and prove the first equ?
lol sry i m noob
zengrz 2 years ago
赞一个
wdy760408 3 years ago
excellent teaching
TURRRRRBO 3 years ago
To PengTitus:
Good video.
Prove Cauchy Schwarz you may consider (aix +/- bi)^2 >= 0 for all x e R.
atheismius 3 years ago
lol, very good I've understood your inequality proof
OliveiraBR22 4 years ago
good, we want more , thanks
bubu0623 4 years ago
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這講的太讚了
tmwcfh 2 weeks ago
unbelievable video!
zengrz 1 month ago
amazing 太棒了!
cyberlancer 2 years ago
sry but why can u change the first equ to (a1+tb1)^2 + (a2+tb2)^2.... and prove the first equ?
lol sry i m noob
zengrz 2 years ago
赞一个
wdy760408 3 years ago
excellent teaching
TURRRRRBO 3 years ago
To PengTitus:
Good video.
Prove Cauchy Schwarz you may consider (aix +/- bi)^2 >= 0 for all x e R.
atheismius 3 years ago
lol, very good I've understood your inequality proof
OliveiraBR22 4 years ago
good, we want more , thanks
bubu0623 4 years ago