Complex Fractions
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Uploader Comments (MuchoMath)
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All Comments (22)
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Well... I really like your youtube username aha :)
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Your are the best math teacher and thanks for your help!
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can you pls.. solve a higher no. i
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thanks dude you're enthusiasm and easy to get explanation helped me understand this, i probably don't even have to go to class later this evening :DD
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YOUR AWESOME I GET IT
I wish you were my math teacher :[
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wow brutal! the best teacher!
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why always denominator can be cancelled? how about the numerator anyway? on the third example..
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YOUR THE BEST TEACHER EVER!!!!
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awesome thanks, helps for those who can't remember steps
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Get to work Erin! Go for the "A"!
MuchoMath 8 months ago
for the part where u said it works for any # what about the # 16
SuperGaara1 1 year ago
@SuperGaara1 If you sum the digits to any number and this sum is divisible by 3 then the number is divisible by 3. The number 16 is not divisible by 3 since 1+6=7 and 7 is not divisible by 3. Let's look at 1,458. Notice when you add the digits together we get 1+4+5+8 which equal 18. Since 18 is divisible by 3, this means 1,458 is divisible by 3. This always works! Kung Fu math!
MuchoMath 1 year ago
Very helpful and easy to understand, thank you. :)
isisncali 1 year ago
Glad I could help. Go for the "A"!
MuchoMath 1 year ago