3.5a Limits at Infinity - Calculus

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Uploaded by on Jun 16, 2009

Check out all of my Calculus Videos and Notes at: http://wowmath.org/Calculus/CalculusNotes.html

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Uploader Comments (RobbWorld)

  • actually its going to be a horizontal asymptote, saying tangent i think implies your talking about a line that originates from a curved line, also the horizontal asymptote in the first problem will actually be the same as negative infinity also.

  • @colinwar

    Thank you for telling me I said tangent line over asymptote. They are horizontal asymptotes. Thanks.

  • Thanks so much, I actually get it now! :D

  • @minaminamelody

    That's awesome. I have a lot more videos at wowmath.org

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All Comments (11)

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  • @aliaksandrhn he did do 3..

  • @txxli @YaStrange1 no since you're dividing 3x by x so the x cancels out

  • Nice

  • He actually messed up on the last one. The correct answer is positive 3, not negative 3. He lost a minus in the denominator. You can also see the mistake when you graph this function on Ti-84 when it is clearly shown that as x goes to negative infinity the function approaches positive 3, not a negative 3.

  • @YaStrange1 yeah it should be.......

  • at 18c shouldnt the denominator have 3/x-1/x?

  • :) thank you so so so much!!

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