@tarmozia the general formula for the area of a circle is r^2 = x^2 + y^2 where r is the radius and (x,y) is a point on the circle. We want to find an expression for the part of the circle above the x-axis. If we solve r^2 = x^2 + y^2
for y by subtracting x^2 from both sides and taking the square root we get y = squareroot(r^2 - x^2). I hope this
@tarmozia sorry. remember when we take the square root it will be +/- (plus or minus) the square root of
r^2 - x^2 so the part of the circle above the x axis has the formula PLUS squareroot(r^2 - x^2). The part below
the x-axis is MINUS squareroot(r^2 - x^2). Think back to when you take the square root of say 4. It is +/-2 because (-2)^2 = 4 and (2)^2 =4. Let me know if you have any further questions.
great video i could not understand . how did you get y=^r2-x2.
thanks
tarmozia 5 months ago
@tarmozia the general formula for the area of a circle is r^2 = x^2 + y^2 where r is the radius and (x,y) is a point on the circle. We want to find an expression for the part of the circle above the x-axis. If we solve r^2 = x^2 + y^2
for y by subtracting x^2 from both sides and taking the square root we get y = squareroot(r^2 - x^2). I hope this
helps to answer your question.
leettab 5 months ago
@leettab
it did but shouldn't it be half b/s we are finding the upper circle only..
tarmozia 5 months ago
@tarmozia sorry. remember when we take the square root it will be +/- (plus or minus) the square root of
r^2 - x^2 so the part of the circle above the x axis has the formula PLUS squareroot(r^2 - x^2). The part below
the x-axis is MINUS squareroot(r^2 - x^2). Think back to when you take the square root of say 4. It is +/-2 because (-2)^2 = 4 and (2)^2 =4. Let me know if you have any further questions.
leettab 5 months ago
Thank you so much, you did something my prof. couldn't do!
iiCeMaN69z 5 months ago
@iiCeMaN69z your welcome. glad to be of help
leettab 5 months ago