Probability Distributions (Part one)
Uploader Comments (DrAlemi)
Video Responses
All Comments (5)
-
The expected value (mean) of a discrete random variable (a counted variable) whose probability is described by a p.m.f. (probability mass function) is not the same as the expected value of a continuous random variable (a measured variable) whose probability is described by a p.d.f. ( probability density function). The p.m.f. uses sigma notation. The p.d.f uses integral notation...at 2:23 the video uses the wrong notation. Don't post incorrect information, please.
-
me 2 i have the same problem i got 0.12 what am i missing ???????
-
Thanks for the video, I got 0.14 too.
Ultar
-
0,06 + 0,08 + 0 + 0 = 0.12 ? Did I miss something? The Expected medication error is the some of the products of the probability and their values! So it should be 0,14
-
Very good video.
This is a good point and shows a rounding error.
DrAlemi 2 years ago
Thank you for your comments. I hope you could also find part 2 and 3.
DrAlemi 4 years ago