The p-Series Test
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for the second example, I thought you could only apply the p-series test if the sum is from n = 1 to infinity, not 4
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Sure thing. Problems with Trig or ln/log/e are the tricky ones for me.
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Nice Quote !
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what if your bound are between 0 to 1? i've been hearing that the converging and diverging part flip
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i have a question with n/(n+1)^3
but my solution says that p=2 not 3?
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Please do an example with a trig, such as cos n pi / n^4 or something of the sort.
Thanks.
MrSoysauce2rice 4 months ago
@MrSoysauce2rice Good suggestion! I will when I get a chance but I would use the alternating series test since cos(n*pi) alternates from -1 to 1.
bullcleo1 4 months ago
if you think of this as n/n^3, it would simplify to 1/n^2 so p = 2.
bullcleo1 1 year ago