Maybe you can't walk on the swamp water because your surface area remains proportional to your weight and thus exert the same number of pounds per square inch on the surface.
@SUMD123 No. The surface area wouldn't be proportional the weight. Area has dimensions L^2 while volume has dimensions L^3. The decrease in size should decrease the weight more drastically than it should decrease the area of contact.
@SUMD123 You make an interesting point. The shear stress Link exerts after he shirnks would be less than the shear stress he exerts when he is full size. However, this shear stress would still increase the apparent viscosity of the fluid, albeit to a lesser extent than when Link is at normal size. It would be interesting to calculate how fast Link would need to run in order to remain above the fluid for normal size and Minish size.
Maybe you can't walk on the swamp water because your surface area remains proportional to your weight and thus exert the same number of pounds per square inch on the surface.
SUMD123 1 year ago
@SUMD123 No. The surface area wouldn't be proportional the weight. Area has dimensions L^2 while volume has dimensions L^3. The decrease in size should decrease the weight more drastically than it should decrease the area of contact.
ASDFsan 1 year ago
@ASDFsan Well, then there would be less pounds per square inch and that lowered value would prevent the non-Newtonian liquid from becoming viscous.
SUMD123 1 year ago
@SUMD123 You make an interesting point. The shear stress Link exerts after he shirnks would be less than the shear stress he exerts when he is full size. However, this shear stress would still increase the apparent viscosity of the fluid, albeit to a lesser extent than when Link is at normal size. It would be interesting to calculate how fast Link would need to run in order to remain above the fluid for normal size and Minish size.
ASDFsan 1 year ago