Ophthalmology - Retinoscopy (Part 1/2)
Uploader Comments (eyevideofan)
All Comments (20)
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A real problem with children is that you must have the child "look in the distance". If the child looks close (accommodation for 20 inches) you will get a measurement that is 2 diopters more plus than in should be. With adults you can instruct them to "look in the distance", and that will provide an accurate measurement.
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@dounoewhoim Actually, he said phoropter
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@2mbilal I see... Got it. Thanks for explaining. Appreciate it :)
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@MarkDavidKnight for a 66 cm working distance its subtract 1.50 DS (1/66cm =1/0.66m=1.50)
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Hi Dr. Thanks for the lectures, but isn't working distance 2.50 and not 1.50? Thanks Dr
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amazing!
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Great illustrations. One correction, however, would be that the subtraction of working distance actually has nothing to do with the vergence of light entering the eye. Instead, it is subtracted because the neutral reflex is found when the practitioner's eye matches the punctum remotum of the neutralized eye. Essentially, the patient is an artificial myope until this working distance is corrected by removing 1.50D or 2.00D (or whatever the dioptric equivalent of your working distance is).
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@dounoewhoim phoropter
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00:39 what is that word? throtter / feropter??? can anyone help, thanks!
@fofocientos
Agreed ... but I would argue that your description is the same thing as described in this video. It's ALWAYS about vergence of light ... whether we are describing converging light (as in this lecture) or coupled optical systems (like you are describing). I prefer the simpler explanation, and try to avoid discussing real/inverted images, far points, and terms like puntum remotum because they don't help someone learn retinoscopy. Appreciate the input.
eyevideofan 5 months ago