Exact Equations Example 3
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Dude, the best diff eqs course I've ever taken, I´m trying to finish my major (electronics engineering) down here in Mexico City, and since I don't have time enough to attend classes at the campus (you know, life in Mexico is harder, and I had to get a job), I searched and found these videos, but in order to go ahead with electric circuits theory, I must find courses as good as these ones, but for Fourier Transform themes, please let me know if you have videos for it
2 years ago 16
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this helped me through my first Diff Equ test...thank you
2 years ago 9
All Comments (24)
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I have an easier way of finding h(y).
1) Remove all terms containing x from N
2) h(y) is the antiderivative of the remaining terms
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I get tripped up at 5:30 (also new to implicit differentiation). Taking the derivative of (x^2*y) gives (2xy + x^2y'), but I'm not clear on how the chain rule was applied. It does look like the product rule though. Is that possibly what was meant?
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@luischuchopepe UNAM?
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wow I'm finally understanding things. I wish our teacher didnt BS through alot of stuff and just told us straight forward like this.
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Why do you need to change the original form? Isn't ___dx + ___dy = 0 what we want?
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U WANTED US TO NOT BEING A ROBOT AND I FINALY UNDERSTANT U WHEN U TAKE THE DIRIVATIVE OF PSI AT THE END AND SHOW US ITS THE SAME
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Thanks
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good stuff!
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well this method is much mechanical and i have to say its brilliant but i m worried about my teachers solution about the Exact DE, as she says y=∫Mdx +∫ (terms of N containing y)dy,
i cant make sure the relation between your solution and my teachers,,can u deifne a little bit that formula???????????/
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I'm having trouble convincing me of what you wrote at around 5:43 (partial derivative of psi with respect to x). In particular, I don't get how the partial of the "2y^3 + 3y" portions aren't just 0 (they're constants in x so wouldn't the derivative of a constant be =0 ???)
stickymage 3 years ago 4
I was actually taking the regular derivative of psi with respect to x (the top 'd' in d/dx does look a little curly which may have confused you). So on the parts with the "y"s, you need to use the chain rule (implicit differentiation).
khanacademy 3 years ago 4