Finite Difference Method for Solving ODEs: Example: Part 2 of 2
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Uploader Comments (numericalmethodsguy)
All Comments (9)
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very important , thanx very much
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Awesome, thank you ! :D
I did homework 1 and got the following results:
u1 = 0.008
u2 = 0.004906
u3 = 0.003646
u4 = 0.003
which is pretty cool to see just how using a centered difference formula can improve accuracy.
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Thank you so much for your videos. You're a great help!
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now i hope i can remember all this during the quiz. inshAllah!. thanks again
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Thanks so much for this. I suspect your videos are going to be the only reason for me getting though my 2nd Year EMTH paper. Keep up the good work.
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Thank you very much for putting up this video, it has been immensely helpful.
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You mentioned that Gauss-Seidel converges if Diagonally Dominant, i thought only Jacobi method converges if Diagonally Dominant, it is not guaranteed for Gauss-Seidal
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how did he just get the exact solution??
erol1991 10 months ago
@erol1991 One gets the exact solution by using Frobenius series. Assume u=summation of a(i)*r**i, with i going from -infinity to +infinity. Substitute in the ODE and you will see that only for i= -1 and i=+1, the coefficient is nonzero. Then apply the boundary conditions (see numericalmethods(.)eng(.)usf(.)edu - click on keyword, click on Finite Diff Method for ODEs, see the example in the textbook chapter)
numericalmethodsguy 10 months ago