Solving logarithmic equations
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korean voice. thanks alot you helped me cover the basics for my exam :)
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I have a question: if i have lograthims in both sides of the equations?
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FINALLY! Thank you so much! I've been stuck on a question like this and didn't realized until now that I was turning the equation into a '0=' too soon.
Thanks a lot! I really appreciate the video!
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in the equation in the top comment (for me) 3log3(x+4)-log3(9)=2 if it is 3log base(b)3 (x+4) -log(b)3 (9)=2 since log(b)3 (9) = 2 then 3log base(b)3 (x+4)=4. what do i do from here???
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thanks that was very helpful ^_^
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also, I used the cancellation law with: ln(2+x) = 2/3 to make e^ln(2+x)= e^2/3. So I was left with 2+x = e^2/3 so I calculated the number on the right. which gave me 2.463. then I substracted 2 from both sides, giving me x = 0.463. but then when I wanted to check it...it was wrong :S
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See what I don't get is: you have 3ln(2+x)...why do you divide both sides instead of raising the 3 to the power of ln(2+x)^3 how am I supposed to know ehn to divide both sides or when to raise to it to a power...:S
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can someone help me how to get the components in order to graph: f(x)=ln((x+2)/(9x-8)) ive been looking for a program to graph this but it does not recognize it... HELP PLEASE i need this for tomorow... atleast some link to a program or a similar tutorial vid of these types of logs
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How do you go about simplifying a logarithmic equation with different bases? I'm given the equation:
log base 5 (x+1) + log base 3 (x+4) = 2
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what if the equation is 3log3(x+4)-log3(9)=2
mgomez6409 1 year ago
@mgomez6409 First bring up the coefficient of 3 on the left as an exponent:
log(3(x+4))^3 - log3(9) = 2. Then simplify to make things easier for you:
log3^3(x+4)^3 - log27 = 2, so log27(x+4)^3 - log27 = 2. Next, condense the logarithmic expressions on the left: log27(x+4)^3/27 = 2. Simplify:
log(x+4)^3 = 2. Then do as I showed in the video, noting that the base of this logarithm is 10.
rlp85hotmail 1 year ago 8
what if the equation is:
2log4-1/3log8=log(x)
Zorglian 1 year ago
@Zorglian First you bring up the coefficients on the left side as exponents:
log 4^2 - log 8^1/3 = log x. Next, simplifiy the exp. terms:
log 16 - log 2 = log x. Next, condense left side:
log 16/2 = log x. This becomes
log 8 = log x. Hence, x = 8. In summary, you condense the log expressions on each side of the equation using properties of logarithms.
rlp85hotmail 1 year ago 2
What if the equation is :
logx32 = 5/6 ?
wangzishow 1 year ago
Write in exponential form: x^(5/6) = 32. Then raise both sides to the power of 6/5.
rlp85hotmail 1 year ago