Compound Interest and e (part 2)

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Uploaded by on Apr 22, 2008

Compounding 100% annual interest continuously over a year converges to e (2.71...)

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  • Sal, your videos are teh awesome! Thanks so much.

    Minor note: (1+1/8760)^8760 is waaaaaaaaaaaay more than 2.714433. I know that's what you get if you just use 0.000114, but when you're raising that beasty to the power of 8760, the stuff that comes after the billionths place MATTERS! The correct number is 2.71812666444. Come on man, didn't you notice something was up when the hourly compounded figure came out lower than the daily compounded figure?

    Keep it real :)

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  • Very enjoyable thank you

  • some great inforamtion here thanks

  • really informative and interesting

  • some great inforamtion here thanks

  • Hey, but how would you do the limit of the compound interest without any reference to e?

  • areeee ...mamu....apnaare wikipedia,,,,maira dehi ,,,apnee bangali,,,,,you made me proud man..!!!..it doesn't happen very often...... love your videos,,,,,

  • @RavellaMusic Balls, no, it's to the power of 3. I was thinking of something stupider.

  • @afreakenracoon Now that we're not doing your homework for you (unless you get a year in which to do it - this isn't some kind of postgraduate thing, is it? ;) ) - the formula is A = P(1-i)^t, where P is the original amount (250,000), i is the interest in the form of a decimal (.15) and t is the elapsed time in years. So to calculate for three years, it's 250,000 times (1-0.15) to the power of 2. (amount time has changed by since P.)

  • @themin91 100% divided by 365 equal 0.27%. You want to convert that percentage into decimal.

    That means, 0,27 / 100 = 0.0027

    After that, you add 1 to it. 1 + 0.0027= 1.0027

    He have a slight miscalculation there. It should have been 1.0027 NOT 1.027

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