Instantaneous Center of Rotation (Part 2) - Engineering Dynamics

Please note: At 6:57 the calculation should be as follows:
r_B/IC = 11.53m; r_C/IC = 6.27m
v_C = ((r_C/IC)/(r_B/IC)) * v_B = (6.27/11.53) * (1 m/s)


Finishing up the example problem from part 1 for instantaneous center of rotation.


Engineering Dynamics - basic concepts and how to solve rigid body kinematics problems using the instantaneous center of rotation. Shows how to locate the instantaneous center of rotation and solve problems using law of sines and law of cosines.

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[golfer564]

You are having way to you much fun! I need to start approaching my homework like you.

[structurefree]

@golfer564 anything can be fun if we approach it with a positive attitude, yo!

[sarab2009]

at 6:57 you did it wrong :P

(6.27/11.53)*(1 m/s)

thank you

[structurefree]

@sarab2009 you are absolutely right! thank you for checking my work. Minus 2 points for me and algebraic errors! At 6:57 the calculation should be as follows:

r_B/IC = 11.53m; r_C/IC = 6.27m

v_C = ((r_C/IC)/(r_B/IC)) * v_B = (6.27/11.53) * (1 m/s)

[liquidstl]

Thanks!



[ogemahracing]

Thank you for this explanation. Its definitely easily than leaning from the textbook.

[quietpunk13]

absolutely cool