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Applications of Integrals - Fluid Forces (Vertical Plate)

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Uploaded by on Feb 14, 2009

An example that uses integration to calculate the fluid force on a vertical plate.

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Education

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Uploader Comments (msumurph)

  • shouldn't the force also depend on the tank size? If I had a pool with a glass on the side lets say at a height of 4, a certain force is acting on the glass. But lets say I make my pool 10 times longer, wouldn't the force be different?

  • @timmy11zoomsharecom The length of the pool does not affect the force. The weight-density of the fluid, the length of the water along your plate, and the depth are what determine the force. We also do a trough problem similar to what you are describing that also illustrates this point, but I don't have a video for that yet.

  • or when you dont have an object... say you have a radius of 2ft and the tank is have filled with oil how do you find the fluid force of one side?

  • @superstud2588 Not sure what shape you are describing. Is your tank a sphere of radius 2 ft? If so, it does not have sides. The technique in this video is used to calculate the fluid pressure on a thin plate, which is some flat surface.

  • @msumurph You messed up, the antiderivative of 3 - y is 3y - y^2 / 2

  • @greywolf424 I know.  At about 5:01 into the video, I do fix it. :)

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  • Thanks! Please make more videos!

  • salamat...(thanks:from the philippines)

  • @msumurph Yah, sorry posted before I got that far

  • @superstud2588 Well, L is the strip length and it depends on the shape of the plate and the location of the y-axis. I usually draw the y-axis down the middle of the plate, If the plate is symmetric about the y-axis, L = 2x.  Of course, you'll have to write x in terms of y before you integrate.

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