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"21" explains the Monty Hall problem

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Uploaded by on May 11, 2008

The character, Ben Campbell, from the movie "21" explains the Monty Hall problem.

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Education

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  • That was a terrible explanation.

  • The teacher bungled the problem by suggesting that the host might be playing mind games. This totally changes the nature of the problem. It is supposed to be clear that the host will always open a door with a goat after you make your original choice.

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  • I hope the movie didn't have him actually end up picking the right door, which would just make his smugness even more insufferable. Yeah, he has a 2 in 3 shot, but it's not 3 in 3.

  • jUST ALL YOU BE QUIET, and enjoy the movie :)

  • @HappyBrotherBeat no, the events are not independent of each other, means that if one event occours (opening of the first door) it changes the nature of the other events as well, its called conditional probability and dependent events, its an application of the famous bayes theorm, search for bayes theorm of probability and read a lil about conditional probability :)

    P(A|B).P(B) = P(B|A).P(A)

    HAPPY LEARNING! :)

  • @sch3ffs Monty always opens a goat door. If you pick a goat door at the start then switch you always get a car. The odds of picking one of the two goats at the start is more likely than picking the car.

  • sch3ffs

    It would only be 50/50 if from the start there were only 2 doors to pick from. since there are 3 doors, 2 of which do not contain the prize you are more likely to pick them over the prize.You WILL pick a goat 66.6% of the time, that's called statistics, you saying, well maybe i will get lucky and pick the car more often is ridiculous. The odds do not change... just because I may flip a coin and 3/4 times it's tails doesn't mean every time it's 75% that the coin will b tails...

  • @abuchanan821 It doesnt, since you cannot ever know if he is or not, and then the probability stay the same.

  • most clear explaination: /watch?v=mhlc7peGlGg

  • @GonnaBeALongLongTime If i pick door number 1 (which is the car) and he shows me door number three. So i now have door number 1 and 2 to choose from. Wouldnt it be a 50 50 chance? Why should i change if the odds are the same? im so confused at how this works, its all about luck, what if everytime i somehow manage to guess the right one first, if i went by this i would always lose.. dont see the logic in it...

  • @HappyBrotherBeat You choose door number 1. You have a 33.3% chance of your door being the car and a 66.7% chance of it being a goat. It's more likely you will pick a goat. Now the host opens a goat door. Now that only a goat and a car remain you can stay, hoping your pick was a car or switch hoping the pick was a goat. Since your pick was most likely a goat switching means it is more likely to win a car. Does that make sense?

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