Alert icon
We're changing our privacy policy. This stuff matters.  Learn more  Dismiss

WildTrig27: Stewart's theorem

Loading...

Sign in or sign up now!
1,941
Loading...
Alert icon
Sign in or sign up now!
Alert icon

Uploaded by on Oct 13, 2008

Stewart's theorem relates measurements on a triangle to an additional line through a vertex. Here we present the rational version, give a simple proof, some examples and an application.

  • likes, 0 dislikes

Link to this comment:

Share to:

Uploader Comments (njwildberger)

  • I see now, in Rational Trigonometry supplementary angles are equal, it's easy to see if you look on the spread protractor. I think it shows that all the spreads of a parallelogram are equal?

  • @benthurston27 That's right.

  • At 1:11 it looks like the original Stewart's Theorem doesn't assume that P3 meets the bottom of the triangle perpendicularly.

  • @benthurston27 That is correct, neither does the modern formulation I give.

see all

All Comments (5)

Sign In or Sign Up now to post a comment!
  • I meant in your diagram at the bottom of the screen in 1:12 you have the spread between P3 and P2 marked as r as well as between P1 and P3, and then in the proof both of those formulas have an (1-r) term instead of (1-r) and (1-r2) if P3 wasn't perpendicular to D. I have no doubt you could still prove it in the general case I was just pointing that out.

Loading...

0 / 00Unsaved Playlist Return to active list
    1. Your queue is empty. Add videos to your queue using this button:
      or sign in to load a different list.
    Loading...Loading...Saving...
    • Clear all videos from this list
    • Learn more