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2 dimensional projectile motion (part 2)

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Uploaded by on Nov 3, 2007

More on 2 dimensional projectile motion

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  • some people just don't appreciate the free knowledge available to them

  • You make Physics fun to learn. I'm glad I found your vids. Thanks alot =D!!!

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  • Thanks a lot for this excellent video but as far as I know, the 'Time of flight (T)' is determined by the formula '2Usinθ/g' , where U is the initial velocity of the particle projected, θ is the angle between the horizontal axis and tangent of the curve, and 'g' is the gravitational constant. As per this formula, on substituting the values we get T = 2(10 x sin45)/10 = 2(10 X 1/√2)/10 =√2 or 1.4 seconds approx.. But you said T = 2√2 or 2.8 seconds approx.. How come?

  • I am very happy to see the vidoe More on 2 dimensional projectile motion after you give this

  • I Love The Video More on 2 dimensional projectile motion It Can Increase My Knowledge

  • Steady I Really Like This Video More on 2 dimensional projectile motion

  • I think Sal made a mistake in this video with finding time

  • If ⌂V=a*t, and you solved for t, it would be ⌂V/a=t, not a/⌂v=t

  • 5:26 COOL. that's the coolest thing i've ever found out on God's green earth cuz i always thought that the difference in angles would make a difference in the time the ball stays in the air.

  • Hel...Sal....There was a mistake,,in the last minutes of this video..

    The actual time. of..the ball in the air should be "sqrt2"

    not 2sqrt 2..ok

  • and in getting the time, is it accurate to use rational numbers?? i mean , in our normal conversation, we dont say " it tooks 2sqrt of 2 before it hits the gound.". its awkward right???

  • @ 8:44 , 10/5sqrt of 2 is= 2sqrt 2. rationalize the denominator and the answer is 2sqrt of 2/ 4. or 1sqrt2/2. i dont know if its still possible to get the lowest term.

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