Chemistry: Buffer solutions. Logarithms (2)
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All Comments (11)
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I'm studying for the DAT and this video is sooooo helpful, thanks
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You are excellent.
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Thanks for the help, but I have a question for clarification. Usually, an equilibrium has a stronger acid and stronger base on one side of the equation, and weaker acid and base, with the equilbrium favoring the weaker side, obviously. So how do you determine a weak acid/base and it's weak conj, acid/base when one side is always stronger?
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You're great dude. I'm taking chem II right now, and these videos clarify things a lot.
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hey its actually. weak acid and strong conjucate base. not weak acid and weak conjugate base. just to clarify things.
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I'm studying for the MCAT and buffers are killing me right now.. Your videos have really helped me, thank you!
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this is will help me a ton!...thanks sir...dont stop posting!!!
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this is very help ful i will spread the word and hopefully ,sir , your sincere efforts would be rewarded....thank you very much
@gdragon666 sorry bro, its weak acid and weak conjugate base. anything strong will just break up and go to completion and thus the reaction wont be true for the reverse reaction. if we add a strong acid the reaction will not shift properly cause itll form water with the strong base. hopefully you didnt get that wrong on an exam :/
cheetah219 1 year ago 4
om goodness, this guy repeats himself so much but it works lol thanks.
deltaforce 2 years ago