natural log and e

Work with natural log (ln) and e. The first of 2 exmaples.

Category:

Education

Tags:

• natural
• log
• and
• e

[DaretoSimplify]

that was very easy to understand! thank you! :)

[Jonin600]

good i understand this now

[leeeshaxo]

thank you!!!

[Polwarthful]

i wonder if your hot maybe you wanna fuck while u teach me logs

[FirstGradeCalculus]

Nice and simple lesson! Thanks much.

[someonetoogoodforyou]

@YourSoDom you sure you copied down the question right? This involves solving a 3rd degree poly. The only real soln is x=0.966. If the question was e^(-2x)+e^(-1x)=0.2, you could make the substitution e^x = u solve a quadratic. Which seems a lot more appropriate

[someonetoogoodforyou]

@humanityexists There are two ways you could do it: The easier way is by separating the ln(0.691/k) into ln(0.691) - ln (k). Then you can rearrange to find ln (k).

This gives you ln(k) = ln(0.691) - 0.001902.

Then powering both sides by e gives you

k = e ^ (ln(0.691) - 0.001902).

Another way you could have done it is by powering both sides by e to begin with and rearranging to find k. Either way you'll get the same answer :)

[humanityexists]

@elflordbob1 have no fear yung'n (*snicker* I laughed as a typed this) I figured it out about 1 month ago

[elflordbob1]

@humanityexists

you cant

but i can

but i wont tell you

because i secretly dont know how

infact idk how i got to this part of youtube

[89Union]

thanks

[MrKrayzieAce]

This is my 4th Period Geometry Teacherr ! (:

[humanityexists]

ok so i have this chemisty problem

ln(.691 / k) = .001902

how would I find k?