Reaction Drive w/ no Ejected Reaction Mass
Uploader Comments (Innateengineer)
All Comments (6)
-
@repatte Thanks for your interest repatte, I will post more videos in the future that discribe the process in more detail.
-
Another perspective is that the weights and their accompanying system act as a single mass that is part of the center of mass. If it is fixed to the center of mass. When the actuator arm(s) pushes against the weights their system will gain -v while at the same time the center of mass will gain +v. Sense they are tied together they will exchange this -/+v and cancel.
-
Your reasoning seems to be along the same lines as a reaction drive of a similar type that I've designed. In any case when you force the weights down with the actuator, how do you prevent the momentum exchange with the center of mass when the weights come in contact with their central axis? The torque will not prevent the exchange from happening because the linear momentum is conserved(is still -v). Which should completely or nearly completely cancel the gain by the center of mass.
If you don't mind, I would like to know your age, Innateengineer?
deathsimpl 1 month ago
@deathsimpl Hi deathsimpl, I am 28 years old. What is your interest in propulsion?
Innateengineer 3 weeks ago