Changes in Motion from Aerodynamic Forces
Uploader Comments (mrg3)
All Comments (30)
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@lveaasaez :D
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@tf08js2 And because air has weight, it produces the atmospheric pressure that we feel on the Earth surface. This pressure is weight/area, so if there´s pressure, then there must be a weight spread over an area, meaning that air has weight/mass. And those people you refer to are just doing pseudoscience. They claim to have the truth but their hyphotesis cannot be proven, meaning that they don´t do science and their statements must be then disregarded. Don´t worry! You have a point, he doesn´!
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@tf08js2 Absolutely. I didn´t read the whole discussion between you and owd but if the point was whether air has mass or not, then the answer is a big YES (in caps) and will have weight because it´s in a gravity field (definition of weight: mass in a grav. field). Air is composed of molecules and those are matter which occupy space and have mass. Therefore, they DO have weight. By the way, rho (density) for air (1 atm, 15ºC) is 1,225 kg/m^3, meaning that 1m^3 of air has a weight of 12 N.
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@lveaasaez He's pathetic really. I have no respect for people who go into scientific discussions just to seem smart if they win the discussion. He was more interested of being right than what actually IS right.
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@lveaasaez I don't think so. What I've read about physics so far makes it very very clear that air has mass, and since it's in a gravity field it also has weight.
I'm educating myself to become an engineer in Physics - and I've spent many many hours reading and thinking and trying to figure out physics.
The other person stopped wanting to know the answer and started to only care about winning the debate.
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@FCbisleybob There´s no such thing as a centrifugal force. Actually, it´s an imaginary force that we can feel but which is not there afterall. By the way, if there was such a thing that opposes the (horizontal) component of lift, then the net force would be zero and there would be no (centripetal) acceleration, meaning that the body (aircraft) would fly in a straight line, which is not the case. Therefore, if u r to fly a curve, you need an acceleration which changes your velocity vector.
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@tf08js2 @oooowwwwdddd What´s going on here? What´s the point of the discussion? Maybe I could help both of you finding then answer to the (for me unknown) question. Maybe you are both right and are arguing on a vague basis. I teach physics so if there´s anything I can do to help you both find a solution, don´t hesitate to contact me.
Kind regards!
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@oooowwwwdddd But for the educated - you just seem ridiculous.
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@oooowwwwdddd And my SOURCES are: Mechanics course book ISBN 9789147051670 by Christer Nyberg, "Våglära och optik" ISBN: 9197249989963 by Jönsson, G och Nilsson and basically all of the scientific articles on Wikipedia in english. They're pretty good. But in the days end, you don't care. You just care about looking smart otherwise you wouldn't spout out nonsense in a discussion of which you know nothing about. For the uneducated your talk sounds fancy and believable.
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@oooowwwwdddd And for the record, my credentials are the following: Programming technique Electrical Measurements Physics - Quantum Phenomena and Nanotechnology Wave Propagation and Introduction to Engineering Physics Automatic Control Linear Algebra Calculus Multivariable Calculus Mathematics - Analytic Functions Mathematics - Systems and Transforms
err where is centrifugal force acting oposite to lift in the turns.
FCbisleybob 2 years ago
There is no "centrifugal force" in turns, there is "centripetal acceleration" towards the center of the circle. The NET force is equal to the total acceleration. The total acceleration can be conceptually broken into two parts: a linear acceleration for speeding up and slowing down and a centripetal acceleration for making turns.
mrg3 2 years ago