Decomposition of Hydrogen peroxide by Potassium permanganate
Uploader Comments (Cforchemistry)
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No, there's nothing wrong with your vid ;) I just thought the initial reaction (when there's no MnO2 yet) would be something like this:
Reduction:
MnO4(-) + 2 H2O + 3 e(-) → MnO2 + 4 OH(-); E° = +1.7V
Oxidation:
H2O2 → O2 + 2 H(+) + 2 e(-)
E° = +0.7V
So from the potentials, this should be possible. Of course, later on as there is more MnO2 present, another more complicated reaction occurs where the MnO2 just catalyzes the dismutation of H2O2 to H2O and O2, correct me if I'm wrong.
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Video Responses
All Comments (29)
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what about 3% H2O2
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Ok now I know I might be asking a stupid question but, when will we use this information in our lives?
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We used Potassium Iodine (KI) and placed it in a closed beaker. The stopper had pressure sensor attached and that way you can measure how much O2 was released.
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thank you, now i can finish my homework ;D
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is there a way of measuring the amount of gas given off?
if so how and is it safe for a classroom experment?
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is there any catalyst which is not powder but rather a solid? i mean something like silver metal but not as expensive as silver. it must be solid so that the surface area remains same?? thanks...
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we used mnO2 in school for catalyst
you did a mistake...the number of the oxygens is not right....test it again....:)
arnrgrerlrors 2 years ago
The equation is not balanced.
Cforchemistry 2 years ago
Can I dispose of the manganese IV by adding water to make a solution, adding sodium carbonate, and filtering it off and throwing it out.
coolliger 2 years ago
you can dispose by adding acid, makeing Mn2+ solution.
Cforchemistry 2 years ago
@Cforchemistry
will any acid do?
coolliger 2 years ago
i would say yes vinegar will do
Cforchemistry 2 years ago