Nucleophilic Substitution : SN1 and SN2
Uploader Comments (evolutionofaudrey)
Top Comments
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wow I understood that in 20 seconds instead of staring at my textbook for hours. I wish my professor would actually do so something like this instead of reading from the book. Thanks for the explanation its so clear and vivid.
All Comments (131)
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don't know why there are some dislikes.
tomorrow, i'll have to write an exam on this topic and this video is a perfect quick overview on this terrifying mechanism :D
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Nice video, although I'm German I understood more than in the German texts.
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It is definitely CH3 because it is a CH connected to C (or any atom for that matter). The C from the CH is alreafy bonded to 2 things (the H in CH as well as the central/main C). C can have only 4 bonds, so 4-2=2. the CH is also bonded to another 2 H's. Therefore, CH+ two H's= CH3.
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AUDREY YOU ROCK
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Great vid, really like it, just wanna say that people also have to know that the time taken for sn1 and sn2 are important and determined by the RDS (Rate Determining Step), which is the first one (and in sn2's case the only one), you did mention that Sn2 is faster but you didn't really kinda specifiy, I dno just felt like throwing that out there :3
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This concept it easy to understand, it would be nice if you made a video explaining how hybridization works and how the Pi and Sigma bonds form in single, double and triple bonds... (PS is this a highschool topic? cuz im taking it in highschool)
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Really good
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what the hell just happpend
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Oh lawd, is that sum massive attack - teardrops?!
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Wow. Ive been staring at my book for hrs now and that 2 minute video made me completely understand Sn1 and Sn2 reactions more than my book and professor did! Thanks for the video!
For your Sn1 rxn, Br is the wrong type of nucleophile. Remember that Sn1 rxns can only occur in the presence of a substrate that is a weak nucleophile/weak base. Br is a strong nucleophile, and therefore would participate in an Sn2 rxn instead of Sn1. For your Sn1 rxn, if you switched H20 as your weak nucleophile for Br, and Br as your leaving group instead of your nucleophile, then your Sn1 rxn would be correct. Good video though.
hoyhoyhoyhoyhoy 2 years ago 6
Thanks for your comments. My reply remains the same: the information was taken directly from the textbook, and while I apologize for its inconsistencies, they rest with the authors of the sixth edition of "Fundamentals of Organic Chemistry". I think it's fabulous that you have this knowledge and are able to share it (so nicely and wisely) with me and my viewers, and I hope they read your comments to clarify the video - but I'm afraid I can't accept corrections. I encourage you to make your own!
evolutionofaudrey 2 years ago 4