SN2, SN1, E2, and E1 reactions (13)

Organic chemistry: SN2, SN1, E2, and E1 reactions and mechanisms.

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(1) SN2
(2) Continued
(3) Continued. SN1
(4) Continued. Methyl, primary, secondary, tertiary, and quaternary carbons
(5) SN1 stereochemistry
(6) The effect of substitution on SN1
(7) The effect of nucleophile quality on SN2 and SN1
(8) E2
(9) Continued
(10) Oxygen nucleophiles
(11) E1
(12) Continued
(13) Continued
(14) Summary


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Education

Tags:

• organic
• chemistry
• mechanisms
• SN2
• SN1
• E2
• E1
• reactions
• bimolecular
• unimolecular
• nucleophilic
• substitution
• elimination
• educational
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[skateshortys212]

You seriously just saved my life!

[jenandroid]

Your videos and worksheets are so helpful! Thank you.

We have H-Br as a product for the Sn1 rxn. Why is it that the Br- doesn't take a hydrogen from H3O+ in the E1 rxn to balance the charges?

[h2okaz]

@ditzychinchilla yes, Sn1 is the major almost always under normal conditions

[tronvidum]

@jenandroid It's because HBr is a strong acid so it wants to LOOSE it's hydrogen (proton). So in nature it is more common for HBr to form Br- rather then Br- to form HBr by gaining a hydrogen, the latter just won't occur in nature. Just remember a strong acid always wants to loose it's hydrogen.

[ellzimac]

thank you so much :D

[ditzychinchilla]

In the last reaction with the Sn1 and the E1, which product is the major one? Is it SN1?

[ledepotesta]

@jenandroid I'm not positive, but if I remember correctly H30 and Br- is the same thing as HBr and H2O since they are in equilibrium

[onlnr2]

You are doing an enormous service to society. I don't believe in god, but I will use the expression "God bless you" anyways. Thank you SO much. Been watching your lectures for two semesters now.

[AdrielandVincentshow]

@HsureWhyNot I was wondering about that, thanks!

[emilycj2005]

lifesaver

[ohmymary1]

LOL @ background noise. YA YA YA YA YA YA YA 0:41

[HsureWhyNot]

@jenandroid

Because the hydrogen will attach to the original nucleophile. Also, he said that HBr is a strong acid and it would want to be deprotonated anyway :)