Power of the Pendulum - Proof of Ultra-Efficiency?
Uploader Comments (Ulianot)
Video Responses
All Comments (25)
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Of course it will slide more easily as you displace the apparatus' center of mass. In many things and real-life applications this is impractical because the pendulum itself would have to be of comparable mass, not to mention delicate equipment that could be damaged in this process of using the displacement of the pendulum's mass, and therefore the apparatus' mass. I still don't think it is even that practical because the back-swing of the pendulum. You should measure precise force involved.
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Sorry bad wording, kinetic and static friction. Check this video out: watch?v=uZGbtK2KBoY
About the tread it is long as hell, you find it if you search for " 12 times more output than input dual mechanical oscillation ".
The thing about this demonstration which people forget, is that if his power measurement device is correct, then just as much energy was input in both situations. What is different is how that energy was spent.
With enough force static friction is overcome...
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Dynamic friction? Where? The stand is still in each example during contact so fictron of the stand is the same. Do you have a link to the OU .com thread? or the name of that thread?
Also i dont see the Walter Lewin video that is relevant to this experiment.
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When this video came out we basically got it worked out at ou.com.
The problem with this video is the way in which energy is used.
In the first case almost everything is lost to static friction while in the second part dynamic friction is the biggest player. The difference of distance traveled is very probably caused by most of the energy being lost to static friction.
(See Walter Lewin's demonstration of their difference at the free MIT videos!)
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I like this video very much! Good job!!!
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I like this video very much! Good job!!!
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You have a great point about the weightlessness at the point of contact. So good of a point, that it raises a few good questions. 1. Where does that energy come from to make the ball weightless? (moves the stand, AND creates less weight at the same time) 2. Is the weight of the ball more than force hammering it?
I'd bet the hammering force was MUCH LESS than the weight of the ball. 3. Does this demonstrate a transfer of centrifugal force that normally is not captured?
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I like this, great demonstration.
The only other thing that i think may influence the travel of your device, is the friction of the table. The second test the center of gravity is in a much different spot than in the first test. This could that influence the travel distance?
You would have to tape the ball to the up right during the first test, to know that answer.
PS, I agree that hand movement does NOT transfer extra energy, and i don't know that the CG will change the results Much ether.
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There is also the superiority of the pendulum in relation to the wheel. Comparisons on the website Veljko Milkovic.
I like it!!!
Agreed. Force * distance is much higher in the secondary approach. The human's arm is pushing the pendulum weight through a lot farther distance...of course the apparatus moves farther once it hits the limit, since it has gained a lot more energy. Inject the same amount of energy into the system, to prove something anomalous. Trip a solenoid, and then measure the totals. A free pendulum won't likely cause any motion then as the energy will be stored by the pendulum arc, not transferred forward.
ArtlyThere 11 months ago
@ArtlyThere
Movement of human arm doesn’t matter if it pass no energy to the pendulum.
Passing of energy is measured by piston movement.
Friction force * path passed by piston equals passed energy to the pendulum.
Ulianot 11 months ago
@Ulianot
The human arm passes the energy to the pendulum via the piston. The friction in the piston (inertia, basically) conveys it into the system. The work input into the system thusly is not measured by the piston's compression alone, but also via force x distance of the arm's through-motion. In the second example, the piston compresses only when the input force exceeds its friction, a smaller portion of the total stroke. Until then, the arm's force is transmitted to the pendulum directly.
ArtlyThere 11 months ago
@ArtlyThere
You are right that before piston start moving the hand can pass some energy into the system, but only if it can move the ball by force smaller then friction of the piston. Once the piston start moving we wouldn’t care what the hand is doing.
Ulianot 11 months ago
You must distinguish between force alone, and the way the force are travelling - energy. In the first experiment the force are traveling only 1mm at the time. When the pendulum are released, you apply the same force over a much greater distance. Hence you apply much more energy in the last part of the experiment, and therfor the rig will move accordingly. The energy transformation from your hand are also highly inefficient, so it appears that you spend the same energy in both experiments.
jallaguri 11 months ago
@jallaguri
Working force is only friction force in the piston, and it passes the same length in both experiments. Movement of the hand is not important at all. We can play around the hand and if piston didn’t change its length then experiment is correct.
Ulianot 11 months ago