Projectile motion (part 3)

An example of solving for the final velocity when you know the change in distance, time, initial velocity, and acceleration

Category:

Education

Tags:

• physics
• projectile
• motion
• acceleration
• velocity
• khan

[polos505]

I think you deserve to get a lot of money for your teaching,just by watching those videos I have learned more than my physic class.

[SimeonBerson10101]

at 0:40 he repeats the equation as given from the previous video, but didnt the previous video state the equation as vf^2=vi^2+2ad?

where'd the acceleration go??

[Kricardose]

I am very happy to see the vidoe An example of solving for the final velocity when you know the change in distance, time, initial velocity, and acceleration after you give this

[bebeheuy]

I Love The Video An example of solving for the final velocity when you know the change in distance, time, initial velocity, and acceleration It Can Increase My Knowledge

[Mjhond]

Steady I Really Like This Video An example of solving for the final velocity when you know the change in distance, time, initial velocity, and acceleration

[soopa123]

@blo0dyme so true, thign is, whe nu look for these videos it means you want to learn it ... when ur at school ur forced to learn it ... that may be the difference oh and ofc hes a great teacher

[kaathrynncruz]

Those 4 dislikes are 4 jealous physics teachers.

[CrazyKing89]

why don't you write the initial velocity as U? As it's standard notation.

[mshterk]

@SimeonBerson10101 i thought that too...

[emptylset]

@amauta5 Actually, if you solve it correctly, you will: Because you are solving for when the penny stops going up V_subf=0 and V_subi=30. Thus, 0^2 = 30^2 + 2(-10)deltaD. -900=-20deltaD. DeltaD=45m. Added to the other distance = 545. Final v sq= 0^2 + 2(-10)(-545) or; V_subf=sqr(10900). No mistakes, just misinterpretations.

[amauta5]

Question, if you first solve how high the penny went up at 30m/s and then get that height and add it to the cliff's height... the final velocity does not equal the same.

findingin how high the penny went: final^2= initial^2 + 2 (gravity) deltaX = 1.5m

Add 1.5 to 500, gives you a free fall equation to find the final velocity^2 = initial^2 + 2 (-10) -501.5) = 100.14

Are we missing soetihng?

[amauta5]

@SimeonBerson10101 he messed up =(