it is simple EE101 - when PF gets closer to unity your measured amps drop, that is how kW of the motor keeps running at the same kW. kW is a function of the horsepower - capacitors do not change the Horse Power. I mean really this is all just a gimmick if you are trying to sell to a residential customer.
Agreed on that.....my statements are more related to a residential v. commerical environment. I can see the validity on a commerical application but do not see the validity on a residential application.
you are correct the kwh at the motor does not change.The reduction of amperage in the system improves the transmission efficency of the system and reduces the line losses. These losses are also measured my the meter and can be significatly reduced. These losses are reduced by the removal of amperage from the system. Kirchoffs Law applies and the sum (IxIxR=watts). The watt reduction in any given aplication can be proven using these formulas and math.The meter will measure this loss reduction
Are you charged in KHW or KVA...makes a big difference. You can reduce the amps but does not mean you reduce the watts. It is not as simple as VxA=W...real power is VxAxPF=Real Power
it is simple EE101 - when PF gets closer to unity your measured amps drop, that is how kW of the motor keeps running at the same kW. kW is a function of the horsepower - capacitors do not change the Horse Power. I mean really this is all just a gimmick if you are trying to sell to a residential customer.
bestos02 1 year ago
Show us the Watt consuming, I know the meter you have there can show it. stop hiding stuff from inosent people!!!
Gigivr6 2 years ago
Agreed on that.....my statements are more related to a residential v. commerical environment. I can see the validity on a commerical application but do not see the validity on a residential application.
TheElectricalGuru 3 years ago
you are correct the kwh at the motor does not change.The reduction of amperage in the system improves the transmission efficency of the system and reduces the line losses. These losses are also measured my the meter and can be significatly reduced. These losses are reduced by the removal of amperage from the system. Kirchoffs Law applies and the sum (IxIxR=watts). The watt reduction in any given aplication can be proven using these formulas and math.The meter will measure this loss reduction
rosmarllc 3 years ago
Are you charged in KHW or KVA...makes a big difference. You can reduce the amps but does not mean you reduce the watts. It is not as simple as VxA=W...real power is VxAxPF=Real Power
TheElectricalGuru 3 years ago